3.19.84 \(\int \frac {(a+b x) (a^2+2 a b x+b^2 x^2)^{3/2}}{(d+e x)^{13/2}} \, dx\)

Optimal. Leaf size=264 \[ -\frac {12 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}{7 e^5 (a+b x) (d+e x)^{7/2}}+\frac {8 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3}{9 e^5 (a+b x) (d+e x)^{9/2}}-\frac {2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^4}{11 e^5 (a+b x) (d+e x)^{11/2}}-\frac {2 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^5 (a+b x) (d+e x)^{3/2}}+\frac {8 b^3 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)}{5 e^5 (a+b x) (d+e x)^{5/2}} \]

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Rubi [A]  time = 0.10, antiderivative size = 264, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.086, Rules used = {770, 21, 43} \begin {gather*} -\frac {2 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^5 (a+b x) (d+e x)^{3/2}}+\frac {8 b^3 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)}{5 e^5 (a+b x) (d+e x)^{5/2}}-\frac {12 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}{7 e^5 (a+b x) (d+e x)^{7/2}}+\frac {8 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3}{9 e^5 (a+b x) (d+e x)^{9/2}}-\frac {2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^4}{11 e^5 (a+b x) (d+e x)^{11/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((a + b*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^(13/2),x]

[Out]

(-2*(b*d - a*e)^4*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(11*e^5*(a + b*x)*(d + e*x)^(11/2)) + (8*b*(b*d - a*e)^3*Sqrt
[a^2 + 2*a*b*x + b^2*x^2])/(9*e^5*(a + b*x)*(d + e*x)^(9/2)) - (12*b^2*(b*d - a*e)^2*Sqrt[a^2 + 2*a*b*x + b^2*
x^2])/(7*e^5*(a + b*x)*(d + e*x)^(7/2)) + (8*b^3*(b*d - a*e)*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(5*e^5*(a + b*x)*(
d + e*x)^(5/2)) - (2*b^4*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(3*e^5*(a + b*x)*(d + e*x)^(3/2))

Rule 21

Int[(u_.)*((a_) + (b_.)*(v_))^(m_.)*((c_) + (d_.)*(v_))^(n_.), x_Symbol] :> Dist[(b/d)^m, Int[u*(c + d*v)^(m +
n), x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[b*c - a*d, 0] && IntegerQ[m] && ( !IntegerQ[n] || SimplerQ[c +
d*x, a + b*x])

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 770

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dis
t[(a + b*x + c*x^2)^FracPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*FracPart[p])), Int[(d + e*x)^m*(f + g*x)*(b/2 + c
*x)^(2*p), x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && EqQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {(a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^{13/2}} \, dx &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {(a+b x) \left (a b+b^2 x\right )^3}{(d+e x)^{13/2}} \, dx}{b^2 \left (a b+b^2 x\right )}\\ &=\frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {(a+b x)^4}{(d+e x)^{13/2}} \, dx}{a b+b^2 x}\\ &=\frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \left (\frac {(-b d+a e)^4}{e^4 (d+e x)^{13/2}}-\frac {4 b (b d-a e)^3}{e^4 (d+e x)^{11/2}}+\frac {6 b^2 (b d-a e)^2}{e^4 (d+e x)^{9/2}}-\frac {4 b^3 (b d-a e)}{e^4 (d+e x)^{7/2}}+\frac {b^4}{e^4 (d+e x)^{5/2}}\right ) \, dx}{a b+b^2 x}\\ &=-\frac {2 (b d-a e)^4 \sqrt {a^2+2 a b x+b^2 x^2}}{11 e^5 (a+b x) (d+e x)^{11/2}}+\frac {8 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{9 e^5 (a+b x) (d+e x)^{9/2}}-\frac {12 b^2 (b d-a e)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{7 e^5 (a+b x) (d+e x)^{7/2}}+\frac {8 b^3 (b d-a e) \sqrt {a^2+2 a b x+b^2 x^2}}{5 e^5 (a+b x) (d+e x)^{5/2}}-\frac {2 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^5 (a+b x) (d+e x)^{3/2}}\\ \end {align*}

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Mathematica [A]  time = 0.09, size = 172, normalized size = 0.65 \begin {gather*} -\frac {2 \sqrt {(a+b x)^2} \left (315 a^4 e^4+140 a^3 b e^3 (2 d+11 e x)+30 a^2 b^2 e^2 \left (8 d^2+44 d e x+99 e^2 x^2\right )+12 a b^3 e \left (16 d^3+88 d^2 e x+198 d e^2 x^2+231 e^3 x^3\right )+b^4 \left (128 d^4+704 d^3 e x+1584 d^2 e^2 x^2+1848 d e^3 x^3+1155 e^4 x^4\right )\right )}{3465 e^5 (a+b x) (d+e x)^{11/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^(13/2),x]

[Out]

(-2*Sqrt[(a + b*x)^2]*(315*a^4*e^4 + 140*a^3*b*e^3*(2*d + 11*e*x) + 30*a^2*b^2*e^2*(8*d^2 + 44*d*e*x + 99*e^2*
x^2) + 12*a*b^3*e*(16*d^3 + 88*d^2*e*x + 198*d*e^2*x^2 + 231*e^3*x^3) + b^4*(128*d^4 + 704*d^3*e*x + 1584*d^2*
e^2*x^2 + 1848*d*e^3*x^3 + 1155*e^4*x^4)))/(3465*e^5*(a + b*x)*(d + e*x)^(11/2))

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IntegrateAlgebraic [A]  time = 42.95, size = 241, normalized size = 0.91 \begin {gather*} -\frac {2 \sqrt {\frac {(a e+b e x)^2}{e^2}} \left (315 a^4 e^4+1540 a^3 b e^3 (d+e x)-1260 a^3 b d e^3+1890 a^2 b^2 d^2 e^2+2970 a^2 b^2 e^2 (d+e x)^2-4620 a^2 b^2 d e^2 (d+e x)-1260 a b^3 d^3 e+4620 a b^3 d^2 e (d+e x)+2772 a b^3 e (d+e x)^3-5940 a b^3 d e (d+e x)^2+315 b^4 d^4-1540 b^4 d^3 (d+e x)+2970 b^4 d^2 (d+e x)^2+1155 b^4 (d+e x)^4-2772 b^4 d (d+e x)^3\right )}{3465 e^4 (d+e x)^{11/2} (a e+b e x)} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((a + b*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^(13/2),x]

[Out]

(-2*Sqrt[(a*e + b*e*x)^2/e^2]*(315*b^4*d^4 - 1260*a*b^3*d^3*e + 1890*a^2*b^2*d^2*e^2 - 1260*a^3*b*d*e^3 + 315*
a^4*e^4 - 1540*b^4*d^3*(d + e*x) + 4620*a*b^3*d^2*e*(d + e*x) - 4620*a^2*b^2*d*e^2*(d + e*x) + 1540*a^3*b*e^3*
(d + e*x) + 2970*b^4*d^2*(d + e*x)^2 - 5940*a*b^3*d*e*(d + e*x)^2 + 2970*a^2*b^2*e^2*(d + e*x)^2 - 2772*b^4*d*
(d + e*x)^3 + 2772*a*b^3*e*(d + e*x)^3 + 1155*b^4*(d + e*x)^4))/(3465*e^4*(d + e*x)^(11/2)*(a*e + b*e*x))

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fricas [A]  time = 0.42, size = 247, normalized size = 0.94 \begin {gather*} -\frac {2 \, {\left (1155 \, b^{4} e^{4} x^{4} + 128 \, b^{4} d^{4} + 192 \, a b^{3} d^{3} e + 240 \, a^{2} b^{2} d^{2} e^{2} + 280 \, a^{3} b d e^{3} + 315 \, a^{4} e^{4} + 924 \, {\left (2 \, b^{4} d e^{3} + 3 \, a b^{3} e^{4}\right )} x^{3} + 198 \, {\left (8 \, b^{4} d^{2} e^{2} + 12 \, a b^{3} d e^{3} + 15 \, a^{2} b^{2} e^{4}\right )} x^{2} + 44 \, {\left (16 \, b^{4} d^{3} e + 24 \, a b^{3} d^{2} e^{2} + 30 \, a^{2} b^{2} d e^{3} + 35 \, a^{3} b e^{4}\right )} x\right )} \sqrt {e x + d}}{3465 \, {\left (e^{11} x^{6} + 6 \, d e^{10} x^{5} + 15 \, d^{2} e^{9} x^{4} + 20 \, d^{3} e^{8} x^{3} + 15 \, d^{4} e^{7} x^{2} + 6 \, d^{5} e^{6} x + d^{6} e^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^(13/2),x, algorithm="fricas")

[Out]

-2/3465*(1155*b^4*e^4*x^4 + 128*b^4*d^4 + 192*a*b^3*d^3*e + 240*a^2*b^2*d^2*e^2 + 280*a^3*b*d*e^3 + 315*a^4*e^
4 + 924*(2*b^4*d*e^3 + 3*a*b^3*e^4)*x^3 + 198*(8*b^4*d^2*e^2 + 12*a*b^3*d*e^3 + 15*a^2*b^2*e^4)*x^2 + 44*(16*b
^4*d^3*e + 24*a*b^3*d^2*e^2 + 30*a^2*b^2*d*e^3 + 35*a^3*b*e^4)*x)*sqrt(e*x + d)/(e^11*x^6 + 6*d*e^10*x^5 + 15*
d^2*e^9*x^4 + 20*d^3*e^8*x^3 + 15*d^4*e^7*x^2 + 6*d^5*e^6*x + d^6*e^5)

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giac [A]  time = 0.24, size = 307, normalized size = 1.16 \begin {gather*} -\frac {2 \, {\left (1155 \, {\left (x e + d\right )}^{4} b^{4} \mathrm {sgn}\left (b x + a\right ) - 2772 \, {\left (x e + d\right )}^{3} b^{4} d \mathrm {sgn}\left (b x + a\right ) + 2970 \, {\left (x e + d\right )}^{2} b^{4} d^{2} \mathrm {sgn}\left (b x + a\right ) - 1540 \, {\left (x e + d\right )} b^{4} d^{3} \mathrm {sgn}\left (b x + a\right ) + 315 \, b^{4} d^{4} \mathrm {sgn}\left (b x + a\right ) + 2772 \, {\left (x e + d\right )}^{3} a b^{3} e \mathrm {sgn}\left (b x + a\right ) - 5940 \, {\left (x e + d\right )}^{2} a b^{3} d e \mathrm {sgn}\left (b x + a\right ) + 4620 \, {\left (x e + d\right )} a b^{3} d^{2} e \mathrm {sgn}\left (b x + a\right ) - 1260 \, a b^{3} d^{3} e \mathrm {sgn}\left (b x + a\right ) + 2970 \, {\left (x e + d\right )}^{2} a^{2} b^{2} e^{2} \mathrm {sgn}\left (b x + a\right ) - 4620 \, {\left (x e + d\right )} a^{2} b^{2} d e^{2} \mathrm {sgn}\left (b x + a\right ) + 1890 \, a^{2} b^{2} d^{2} e^{2} \mathrm {sgn}\left (b x + a\right ) + 1540 \, {\left (x e + d\right )} a^{3} b e^{3} \mathrm {sgn}\left (b x + a\right ) - 1260 \, a^{3} b d e^{3} \mathrm {sgn}\left (b x + a\right ) + 315 \, a^{4} e^{4} \mathrm {sgn}\left (b x + a\right )\right )} e^{\left (-5\right )}}{3465 \, {\left (x e + d\right )}^{\frac {11}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^(13/2),x, algorithm="giac")

[Out]

-2/3465*(1155*(x*e + d)^4*b^4*sgn(b*x + a) - 2772*(x*e + d)^3*b^4*d*sgn(b*x + a) + 2970*(x*e + d)^2*b^4*d^2*sg
n(b*x + a) - 1540*(x*e + d)*b^4*d^3*sgn(b*x + a) + 315*b^4*d^4*sgn(b*x + a) + 2772*(x*e + d)^3*a*b^3*e*sgn(b*x
+ a) - 5940*(x*e + d)^2*a*b^3*d*e*sgn(b*x + a) + 4620*(x*e + d)*a*b^3*d^2*e*sgn(b*x + a) - 1260*a*b^3*d^3*e*s
gn(b*x + a) + 2970*(x*e + d)^2*a^2*b^2*e^2*sgn(b*x + a) - 4620*(x*e + d)*a^2*b^2*d*e^2*sgn(b*x + a) + 1890*a^2
*b^2*d^2*e^2*sgn(b*x + a) + 1540*(x*e + d)*a^3*b*e^3*sgn(b*x + a) - 1260*a^3*b*d*e^3*sgn(b*x + a) + 315*a^4*e^
4*sgn(b*x + a))*e^(-5)/(x*e + d)^(11/2)

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maple [A]  time = 0.06, size = 202, normalized size = 0.77 \begin {gather*} -\frac {2 \left (1155 b^{4} e^{4} x^{4}+2772 a \,b^{3} e^{4} x^{3}+1848 b^{4} d \,e^{3} x^{3}+2970 a^{2} b^{2} e^{4} x^{2}+2376 a \,b^{3} d \,e^{3} x^{2}+1584 b^{4} d^{2} e^{2} x^{2}+1540 a^{3} b \,e^{4} x +1320 a^{2} b^{2} d \,e^{3} x +1056 a \,b^{3} d^{2} e^{2} x +704 b^{4} d^{3} e x +315 a^{4} e^{4}+280 a^{3} b d \,e^{3}+240 a^{2} b^{2} d^{2} e^{2}+192 a \,b^{3} d^{3} e +128 b^{4} d^{4}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}{3465 \left (e x +d \right )^{\frac {11}{2}} \left (b x +a \right )^{3} e^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^(13/2),x)

[Out]

-2/3465/(e*x+d)^(11/2)*(1155*b^4*e^4*x^4+2772*a*b^3*e^4*x^3+1848*b^4*d*e^3*x^3+2970*a^2*b^2*e^4*x^2+2376*a*b^3
*d*e^3*x^2+1584*b^4*d^2*e^2*x^2+1540*a^3*b*e^4*x+1320*a^2*b^2*d*e^3*x+1056*a*b^3*d^2*e^2*x+704*b^4*d^3*e*x+315
*a^4*e^4+280*a^3*b*d*e^3+240*a^2*b^2*d^2*e^2+192*a*b^3*d^3*e+128*b^4*d^4)*((b*x+a)^2)^(3/2)/e^5/(b*x+a)^3

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maxima [B]  time = 0.77, size = 393, normalized size = 1.49 \begin {gather*} -\frac {2 \, {\left (231 \, b^{3} e^{3} x^{3} + 16 \, b^{3} d^{3} + 40 \, a b^{2} d^{2} e + 70 \, a^{2} b d e^{2} + 105 \, a^{3} e^{3} + 99 \, {\left (2 \, b^{3} d e^{2} + 5 \, a b^{2} e^{3}\right )} x^{2} + 11 \, {\left (8 \, b^{3} d^{2} e + 20 \, a b^{2} d e^{2} + 35 \, a^{2} b e^{3}\right )} x\right )} a}{1155 \, {\left (e^{9} x^{5} + 5 \, d e^{8} x^{4} + 10 \, d^{2} e^{7} x^{3} + 10 \, d^{3} e^{6} x^{2} + 5 \, d^{4} e^{5} x + d^{5} e^{4}\right )} \sqrt {e x + d}} - \frac {2 \, {\left (1155 \, b^{3} e^{4} x^{4} + 128 \, b^{3} d^{4} + 144 \, a b^{2} d^{3} e + 120 \, a^{2} b d^{2} e^{2} + 70 \, a^{3} d e^{3} + 231 \, {\left (8 \, b^{3} d e^{3} + 9 \, a b^{2} e^{4}\right )} x^{3} + 99 \, {\left (16 \, b^{3} d^{2} e^{2} + 18 \, a b^{2} d e^{3} + 15 \, a^{2} b e^{4}\right )} x^{2} + 11 \, {\left (64 \, b^{3} d^{3} e + 72 \, a b^{2} d^{2} e^{2} + 60 \, a^{2} b d e^{3} + 35 \, a^{3} e^{4}\right )} x\right )} b}{3465 \, {\left (e^{10} x^{5} + 5 \, d e^{9} x^{4} + 10 \, d^{2} e^{8} x^{3} + 10 \, d^{3} e^{7} x^{2} + 5 \, d^{4} e^{6} x + d^{5} e^{5}\right )} \sqrt {e x + d}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^(13/2),x, algorithm="maxima")

[Out]

-2/1155*(231*b^3*e^3*x^3 + 16*b^3*d^3 + 40*a*b^2*d^2*e + 70*a^2*b*d*e^2 + 105*a^3*e^3 + 99*(2*b^3*d*e^2 + 5*a*
b^2*e^3)*x^2 + 11*(8*b^3*d^2*e + 20*a*b^2*d*e^2 + 35*a^2*b*e^3)*x)*a/((e^9*x^5 + 5*d*e^8*x^4 + 10*d^2*e^7*x^3
+ 10*d^3*e^6*x^2 + 5*d^4*e^5*x + d^5*e^4)*sqrt(e*x + d)) - 2/3465*(1155*b^3*e^4*x^4 + 128*b^3*d^4 + 144*a*b^2*
d^3*e + 120*a^2*b*d^2*e^2 + 70*a^3*d*e^3 + 231*(8*b^3*d*e^3 + 9*a*b^2*e^4)*x^3 + 99*(16*b^3*d^2*e^2 + 18*a*b^2
*d*e^3 + 15*a^2*b*e^4)*x^2 + 11*(64*b^3*d^3*e + 72*a*b^2*d^2*e^2 + 60*a^2*b*d*e^3 + 35*a^3*e^4)*x)*b/((e^10*x^
5 + 5*d*e^9*x^4 + 10*d^2*e^8*x^3 + 10*d^3*e^7*x^2 + 5*d^4*e^6*x + d^5*e^5)*sqrt(e*x + d))

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mupad [B]  time = 2.95, size = 353, normalized size = 1.34 \begin {gather*} -\frac {\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}\,\left (\frac {8\,x\,\left (35\,a^3\,e^3+30\,a^2\,b\,d\,e^2+24\,a\,b^2\,d^2\,e+16\,b^3\,d^3\right )}{315\,e^9}+\frac {2\,b^3\,x^4}{3\,e^6}+\frac {630\,a^4\,e^4+560\,a^3\,b\,d\,e^3+480\,a^2\,b^2\,d^2\,e^2+384\,a\,b^3\,d^3\,e+256\,b^4\,d^4}{3465\,b\,e^{10}}+\frac {8\,b^2\,x^3\,\left (3\,a\,e+2\,b\,d\right )}{15\,e^7}+\frac {4\,b\,x^2\,\left (15\,a^2\,e^2+12\,a\,b\,d\,e+8\,b^2\,d^2\right )}{35\,e^8}\right )}{x^6\,\sqrt {d+e\,x}+\frac {a\,d^5\,\sqrt {d+e\,x}}{b\,e^5}+\frac {x^5\,\left (a\,e+5\,b\,d\right )\,\sqrt {d+e\,x}}{b\,e}+\frac {5\,d\,x^4\,\left (a\,e+2\,b\,d\right )\,\sqrt {d+e\,x}}{b\,e^2}+\frac {d^4\,x\,\left (5\,a\,e+b\,d\right )\,\sqrt {d+e\,x}}{b\,e^5}+\frac {10\,d^2\,x^3\,\left (a\,e+b\,d\right )\,\sqrt {d+e\,x}}{b\,e^3}+\frac {5\,d^3\,x^2\,\left (2\,a\,e+b\,d\right )\,\sqrt {d+e\,x}}{b\,e^4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*x)*(a^2 + b^2*x^2 + 2*a*b*x)^(3/2))/(d + e*x)^(13/2),x)

[Out]

-((a^2 + b^2*x^2 + 2*a*b*x)^(1/2)*((8*x*(35*a^3*e^3 + 16*b^3*d^3 + 24*a*b^2*d^2*e + 30*a^2*b*d*e^2))/(315*e^9)
+ (2*b^3*x^4)/(3*e^6) + (630*a^4*e^4 + 256*b^4*d^4 + 480*a^2*b^2*d^2*e^2 + 384*a*b^3*d^3*e + 560*a^3*b*d*e^3)
/(3465*b*e^10) + (8*b^2*x^3*(3*a*e + 2*b*d))/(15*e^7) + (4*b*x^2*(15*a^2*e^2 + 8*b^2*d^2 + 12*a*b*d*e))/(35*e^
8)))/(x^6*(d + e*x)^(1/2) + (a*d^5*(d + e*x)^(1/2))/(b*e^5) + (x^5*(a*e + 5*b*d)*(d + e*x)^(1/2))/(b*e) + (5*d
*x^4*(a*e + 2*b*d)*(d + e*x)^(1/2))/(b*e^2) + (d^4*x*(5*a*e + b*d)*(d + e*x)^(1/2))/(b*e^5) + (10*d^2*x^3*(a*e
+ b*d)*(d + e*x)^(1/2))/(b*e^3) + (5*d^3*x^2*(2*a*e + b*d)*(d + e*x)^(1/2))/(b*e^4))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b**2*x**2+2*a*b*x+a**2)**(3/2)/(e*x+d)**(13/2),x)

[Out]

Timed out

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